y=ln[(x+1)(2x-1)]

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Solution for y=ln[(x+1)(2x-1)] equation: 


Simplifying
y = ln[(x + 1)(2x + -1)]

Reorder the terms:
y = ln[(1 + x)(2x + -1)]

Reorder the terms:
y = ln[(1 + x)(-1 + 2x)]

Multiply (1 + x) * (-1 + 2x)
y = ln[(1(-1 + 2x) + x(-1 + 2x))]
y = ln[((-1 * 1 + 2x * 1) + x(-1 + 2x))]
y = ln[((-1 + 2x) + x(-1 + 2x))]
y = ln[(-1 + 2x + (-1 * x + 2x * x))]
y = ln[(-1 + 2x + (-1x + 2x2))]

Combine like terms: 2x + -1x = 1x
y = ln[(-1 + 1x + 2x2)]
y = [-1 * ln + 1x * ln + 2x2 * ln]
y = [-1ln + 1lnx + 2lnx2]

Solving
y = -1ln + 1lnx + 2lnx2

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Simplifying
y = -1ln + 1lnx + 2lnx2

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